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A car of mass m is driven with acceleration 'a' along a straight level road against a constant external resistive force 'R'. when velocity of car is 'V', the rate at which the engine of car is doing work will be

\[(a)\;RV \quad (b)\;maV \quad (c)\;(R+ma)V \quad (d)\;(ma-R)V\]

1 Answer

Answer: (R+ma)V
Force required to oppose resistive force R and move with acceleration a is $R+ma$
Power of a body is defined as the rate at which the body can do the work. Power=Force $ \times $ Velocity
answered Jul 18, 2013 by meena.p
edited Aug 27, 2014 by balaji.thirumalai

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