Want to ask us a question? Click here
Browse Questions
 Ad
0 votes

# A car of mass m is driven with acceleration 'a' along a straight level road against a constant external resistive force 'R'. when velocity of car is 'V', the rate at which the engine of car is doing work will be

$(a)\;RV \quad (b)\;maV \quad (c)\;(R+ma)V \quad (d)\;(ma-R)V$

Can you answer this question?

## 1 Answer

0 votes
Answer: (R+ma)V
Force required to oppose resistive force R and move with acceleration a is $R+ma$
Power of a body is defined as the rate at which the body can do the work. Power=Force $\times$ Velocity
$\qquad=(R+ma)V$
answered Jul 18, 2013 by
edited Aug 27, 2014

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer