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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2009

A conducting circular loop is placed in a uniform magnetic field 0.04T with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2 mm/s. The induced emf in the loop when the redius is 2 cm is :

( A ) $0.8\pi{\mu}V$
( B ) $1.6\pi{\mu}V$
( C ) $3.2\pi\mu V$
( D ) $4.8\pi{\mu}V$

1 Answer

A= (Pi)(sqr(r)). It is given  dr/dt = -2 mm/sec .

Thus dA/dt = 2(pi)r(dr/dt).

mod(E at r= 2cm) = B*dA/dt ( take only the mod of dr/dt)

the answer is C
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