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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2009
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Q)

The mean free path of electrons in a metal is $4\times10^-8$ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m :


( A ) $8\times10^{-11}$
( B ) $5\times10^7$
( C ) $8\times10^7$
( D ) $5\times10^{-11}$

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