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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2009
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Q)

From the following bond energies : <br> H – H bond energy : 431.37 kJ $mol^{–1}$ <br> C = C bond energy : 606.10 kJ $mol^{–1}$ <br> C – C bond energy : 336.49 kJ $mol^{–1}$ <br> C – H bond energy : 410.50 kJ $mol^{–1}$ <br> Enthalpy for the reaction, <br> <img src="http://clay6.com/mpaimg/208_a.jpg "/>


( A ) $1523.6 Kj mol^{-1}$
( B ) $120.0Kj mol^{-1}$
( C ) $–243.6 Kj mol^{-1}$
( D ) $553.0 Kj mol^{-1}$

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A)
For the given reaction, enthalpy of reaction can be calculated as Read more on Sarthaks.com - https://www.sarthaks.com/227380/from-the-following-bond-energies-h-h-bond-energy-431-37-kj-mol-1
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