logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Work, Power and Energy

In the figure shown, a particle is released from the position A on a smooth track. When particle reaches B, the normal reaction on it by the track is

 

a) mg b) 2mg c) $\large\frac{2}{3}$ mg d) $\large\frac{m^2g}{h}$

1 Answer

By conservation of energy
At A and B
$mg(3h)=mg(2h)+\large\frac{1}{2}$$mv^2$
When $v=velocity $ at B
$gh=\large\frac{1}{2} $$v^2$
$v=\sqrt {2gh}$
Also at B for the body to stay on the track, $N+mg=\large\frac{mv^2}{h}$
Substituting for $v^2$
$N+mg =2 mg$
$N=mg$
Hence a is the correct answer.
answered Jul 18, 2013 by meena.p
edited Jun 1, 2014 by lmohan717
 

Related questions

...