Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
0 votes

In the figure shown, a particle is released from the position A on a smooth track. When particle reaches B, the normal reaction on it by the track is


a) mg b) 2mg c) $\large\frac{2}{3}$ mg d) $\large\frac{m^2g}{h}$
Can you answer this question?

1 Answer

0 votes
By conservation of energy
At A and B
When $v=velocity $ at B
$gh=\large\frac{1}{2} $$v^2$
$v=\sqrt {2gh}$
Also at B for the body to stay on the track, $N+mg=\large\frac{mv^2}{h}$
Substituting for $v^2$
$N+mg =2 mg$
Hence a is the correct answer.
answered Jul 18, 2013 by meena.p
edited Jun 1, 2014 by lmohan717

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App