Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
0 votes

In the arrangement shown mass m is released from rest with the spring unstretched . The force constant of spring is K. The maximum extension in the spring

\[(a)\;x_m=\frac{2mg}{k} \quad (b)\;x_m=\frac{mg}{k} \quad (c)\;x_m=\frac{mg}{2k}\quad (d)\;x_m=\frac{k}{2 mg}\]

Can you answer this question?

1 Answer

0 votes
When the spring extends to maximum extension $x_0$
The potential energy of spring= gravitational potential of block
$mgx_m=\large\frac{1}{2}$$ k x_m^2$
Hence a is the correct answer.


answered Jul 18, 2013 by meena.p
edited Feb 10, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App