# The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures $T_1$ and $T_2$ $(T_1>T_2)$. The rate of heat transfer, $\frac{dQ}{dt}$ through the rod in a steady dt state is given by :
( A ) $\frac{dQ}{dt}=\frac{KA(T_{1}-T_{2})}{L}$
( B ) $\frac{dQ}{dt}=\frac{KL(T_{1}-T_{2})}{A}$
( C ) $\frac{dQ}{dt}={KLA(T_{1}-T_{2})}$
( D ) $\frac{dQ}{dt}=\frac{K(T_{1}-T_{2})}{LA}$