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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2010
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Q)

The dimension of $\frac {1}{2}\epsilon_0 E^2$ , where $\epsilon_0$ is permittivity of free space and E is electric field, is –


( A ) $MLT^{-1}$
( B ) $ML^{2}T^{-1}$
( C ) $ML^{2}T^{-2}$
( D ) $ML^{-1}T^{-2}$

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