# The number of atoms in 0.1 mol of a triatomic gas is : ($N_A=6.02\times10^{23} mol^{-1}$)
( A ) $3.600\times10^{23}$
( B ) $1.800\times10^{22}$
( C ) $6.026\times10^{22}$
( D ) $1.806\times10^{23}$