Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
0 votes

Ice cube of size $100\;cm$ and area of base $(500 m \times 50 m)$ is floating in a tank partially filled with water. The change in gravitational potential energy, when ice melts completely (density of Ice is $900\;kg/m^3$)

\[(a)\;-0.072\;J \quad (b)\;-0.24\;J \quad (c)\;-0.016\;J \quad (d)\;-0.045\;J\]
Can you answer this question?

1 Answer

0 votes
Relative density of ice is 0.9. Hence $90\%$ of volume of ice is immused in water.
When ice melts completely level of water does not change
Therefore the change in $CG=GG'=0.5\; cm$
Change in potential energy
$\Delta V=-mgh$
$\qquad=-(0.1)^3(900)(10)(0.5 \times 10^{-2})J$
Hence d is the correct answer.


answered Jul 20, 2013 by meena.p
edited Feb 10, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App