Comment
Share
Q)

# A certain particle carries $2.5 \times 10^{-16}\;C$ of static electric charge. Calculate the number of electrons present in it .

$\begin{array}{1 1} (a)\;1560 \\ (b)\;1345 \\ (c)\;1259 \\ (d)\;1660\end{array}$

Charge carried by one electron $=1.6022 \times 10^{-19}\;C$
$\therefore$ Electrons present in particle carrying $2.5 \times 10^{-16}$
C charge $=\large\frac{2.5 \times 10^{-16}\;C}{1.6022 \times 10^{-19}\;C}$$=1560$