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Questions  >>  SAT  >>  Chemistry  >>  Atomic Structure
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Q)

The energy of second Bohr orbit of hydrogen atom is $-328\;kJ mol^{-1}$ , hence energy of fourth Bohr orbit would be

$\begin{array}{1 1} (a)\;-41\;kJ \;mol^{-1} \\ (b)\;-82\;kJ \;mol^{-1} \\ (c)\;-164\;kJ\;mol^{-1} \\ (d)\;-1312\;kJ\;mol^{-1}\end{array} $

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A)
Solution :
$E_n= \large\frac{E_1}{n^2}$
$E_2= \large\frac{E_1}{(2)^2}$$=-328\;kJ \;mol^{-}$
$E_1=-328 \times 4 \;kJ mol^{-1}$
$E_4=\large\frac{E_1}{(4)^2}$
$\qquad= \large\frac{-328 \times 4}{(4)^2}$$\;kJ\;mol^{-1}$
$\qquad= -82\;kJ\;mol^{-1}$
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