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If $ix^2-x+12i=0$ then $x$ = ?

(A) $x=4i,\:\:3i$
(B) $x=4i,\:\:-3i$
(C) $x=-4i,\:\:3i$
(D) $x=-4i,\:\:-3i$

1 Answer

Toolbox:
  • If $ax^2+bx+c=0$, then $x=\large\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
$If\:\:\:ix^2-x+12i=0$, then
$x=\large\frac{1\pm\sqrt{1-48i^2}}{2i}$
$=\large\frac{1\pm 7}{2i}$
$=\large\frac{4}{i}\:\:$$or\:\:\large\frac{-3}{i}$
$=-4i\:\:or\:\:3i$
answered Jul 24, 2013 by rvidyagovindarajan_1
 

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