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The quadratic eqn., whose one root is $2-\sqrt 3i$ is given by ?

$\begin{array}{1 1}(A)x^2+4x-7=0 \\ (B) x^2-4x+7=0 \\ (C) x^2+4x+7 =0 \\(D) x^2-4x-7=0 \end{array}$

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If one root is $2-\sqrt 3i$ then the other root is $ 2+\sqrt 3i$
Sum of the roots $=4$ and Product of the roots $=7$
$\therefore $ The equation is $x^2-4x+7=0$
answered Jul 27, 2013 by rvidyagovindarajan_1

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