If $p>0,\:q>0$, then the roots of $x^2-px-q=0$ are

(A) Imaginary.

(B) Both the roots are real and positive.

(C) Both the roots are real and negative.

(D) Both the roots are of opposite sign.

Toolbox:
• If the degree of a polynomial equation is even with constant term negative then the equation has atleast two real roots with opposite sign.
Given equation $x^2-px-q=0$ is of degree two.
$\therefore$ it has two real roots with opposite sign.