logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

If one root of the eqn., $x^2+px+12=0$ is 4, while the eqn., $x^2+px+q=0$ has equal roots, then the value of $q$=?

(A) $\large\frac{49}{4}$

(B) $\large\frac{4}{49}$

(C) $4$

(D) cannot be determined.

Can you answer this question?
 
 

1 Answer

0 votes
Given: One root of $x^2+px+12=0$ is 4
$\Rightarrow\:16+4p+12=0$
$\Rightarrow\:p=-7$
$x^2+px+q=0$ has equal roots.
$\Rightarrow\:p^2-4q=0$
$\Rightarrow\:49=4q$
$or\:q=\large\frac{49}{4}$
answered Jul 27, 2013 by rvidyagovindarajan_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...