# When 1 kg of ice at $0^oC$ melts to water at $0^oC$, the resulting change in its entropy, taking latent heat of ice to be $80 \; Cal/gm$ is :
( A ) $273 \; Cal/K$
( B ) $293 \; Cal / K$
( C ) $8 \times 10^4\; Cal/K$
( D ) $80 \; Cal/K$