If n = 6, the correct sequence for filling of electrons will be :

Question

( A ) $ ns \to np(n – 1)d \to (n – 2)f $
( B ) $ns \to (n – 2)f \to np \to (n – 1)d$
( C ) $ ns \to (n – 1)d \to (n – 2)f \to np $
( D ) $ns \to (n – 2)f \to (n – 1)d \to np $