# The enthalpy of fusion of water is $1.435 \frac{kcal}{mol}$. The molar entropy change for the melting of ice at $0^{\circ}C$ is :
( A ) $\frac{10.52 cal}{(molK)}$
( B ) $\frac{0.526cal}{(molK)}$
( C ) $\frac{21.04 cal }{(molK)}$
( D ) $\frac{5.260cal} {(molK)}$