Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2015
Answer
Comment
Share
Q)

A particle is executing a simple harmonic motion. Its maximum acceleration is $\alpha$ and maximum velocity is $\beta$. Then, its time period of vibration will be:


( A ) $\frac{2 \pi \beta}{\alpha}$
( B ) $\frac{\beta^2}{\alpha}$
( C ) $\frac{\alpha}{\beta}$
( D ) $\frac{\beta^2}{\alpha^2}$

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...