Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
0 votes

An object of mass m is allowed to fall from rest along a rough inclined plane. The speed of the object at bottom of the plane is proportional to

\[(a)\;m^0 \quad (b)\;m \quad (c)\;m^2 \quad (d)\;m^{-1}\]
Can you answer this question?

1 Answer

0 votes
Using work energy theorem
$\large\frac{1}{2}$$mv^2=mgh-(\mu mg \cos \theta)(\large\frac{h}{\sin \theta})$
where $\large\frac{h}{\sin \theta}$=length of the incline.
'h' hight of incline and $'\theta'$ angle of incline.
$v=\sqrt {2gh-2 \mu gh \cot \theta}$
$ v \;\alpha\; m^0$
Hence a is the correct answer. 


answered Aug 6, 2013 by meena.p
edited Feb 10, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App