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If $3+\sqrt 2 i$ is a root of of $x^2+px+q=0$, then $(p,q)=?$

$\begin{array}{1 1} (6,11) \\ (-6,11) \\ (-11,-6) \\ (11,-6) \end{array} $

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If $3+\sqrt2 i$ is one root then $3-\sqrt 2 i$ is other root.
sum of the roots = $6=-p$
product of the roots =$9+2=11=q$
$\therefore\:(p,q)=(-6,11)$
answered Aug 6, 2013 by rvidyagovindarajan_1
 

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