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# A cyclotron is used to accelerate protons deuterons, $\alpha$- particles etc. If energy attained after acceleration by proton is E, the energy attained by $\alpha$- particle shall be

$(a)\;4\;E\quad (b)\;2\;E \quad (c)\; E \quad (d)\;\frac{E}{4}$

The energy attained by a proton is $E=qv$ where $'q'$ is the charge on proton and v is the potential.
The energy attained by $\alpha$- particle
$E'=(2q)v$ (as $\alpha$ particle has 2q charge )
$\therefore E'=2E$
Hence b is the correct answer.

edited Feb 17, 2014 by meena.p

+1 vote