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Find the absolute maximum value and the absolute minimum value of the following functions in the given intervals: $(iv)\: f (x) = (x-1)^2+3, x \in [– 3, 1] $

This is fourth part of multipart q5

1 Answer

  • $\large\frac{d}{dx}$$(x^n)=nx^{n-1}$
Step 1:
For extreme values $f'(x)=0$
Step 2:
Now we find $f(x)$ at $x=1,-3$
Step 3:
Step 4:
$\therefore$ Absolute maximum value =19 at $x=-3$
Absolute minimum value=3 at $x=1$
answered Aug 7, 2013 by sreemathi.v

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