Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
+1 vote

A bob of pendulum of length 2 m describes an are of a circle in a vertical plane. If the lension in the cord is $2.5$ times the weight of the bob for the position shown, find the velocity of the bobs at that position.

a) 6.22 m

b) 5.66 m

c) 4.20 m

d) 2.44 m


Can you answer this question?

1 Answer

0 votes
Let T be tension in the string
The bob has a centerpetal force $ \large\frac{mv^2}{l}$
$T-mg \cos \theta=\large\frac{mv^2}{l}$
$2 mg-mg \cos 30=\large\frac{mv^2}{2}$
$v=5.66 m/s$
Hence b is the correct answer
answered Aug 7, 2013 by meena.p
edited Jun 13, 2014 by lmohan717

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App