Ask Questions, Get Answers
Menu
X
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
15 Test Series
CBSE XII
Math
JEEMAIN
Math
Physics
Chemistry
Practice Test Series
CBSE XI
Math
NEET
Physics
Chemistry
Biology - XII
Biology - XI
Olympiad class V
Math - 5 Test Series
Olympiad class VI
Math - 5 Test Series
studyplans
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
15 Test Series
CBSE XII
Math
JEEMAIN
Math
Physics
Chemistry
Practice Test Series
CBSE XI
Math
NEET
Physics
Chemistry
Biology - XII
Biology - XI
Olympiad class V
Math - 5 Test Series
Olympiad class VI
Math - 5 Test Series
mobile
exams
ask
sample papers
tutors
pricing
login
X
ASK
Home
>>
JEEMAIN and NEET
>>
Physics
>>
Class11
>>
Work, Power and Energy
A particle of mass m is moving in a circular path of constant radius 'r'. Such that the centripetal acceleration $a_c$ is varying with time as $a_c=k^2rt$ where R is a constant. What is the power on the particle
\[(a)\;2 \pi mk^2r^2t\quad (b)\;mk^2r^2t \quad (c)\; \frac{mk^4r^2t}{3} \quad (d)\;zero\]
jeemain
physics
class11
unit4
work-power-energy
q89
medium
Share
asked
Aug 8, 2013
by
meena.p
retagged
Jul 10, 2014
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1 Answer
Since $a_c=k^2rt^2$
$\large\frac{v^2}{r}$$=k^2rt^2$
$v^2=k^2r^2t^2$
$v=krt$
$F=m \large\frac{dv}{dt}$
$\quad=m kr$
Power $=F.v$
$\qquad=(mkr) \times (krt)$
$\qquad=mk^2r^2t$
Hence b is the correct answer.
answered
Aug 8, 2013
by
meena.p
edited
Jun 13, 2014
by
lmohan717
Please
log in
or
register
to add a comment.
Related questions
Two small particle of equal masses start moving in opposite direction from A in a horizontal circular path of radius r Their tangential velocity at A are v and 2v, respectively as shown. Where will be the first collision in the path of the circle.
jeemain
physics
class11
unit4
work-power-energy
q94
medium
asked
Aug 8, 2013
by
meena.p
1
answer
A particle of mass $ M $is moving in a circle of fixed radius $R$ in such a way that its centripetal acceleration at time $t$ is given by $n^2 R t^2$ where $ n$ is a constant. The power delivered to the particle by the force acting on it, is:
jeemain-2016 physics set c 10042016
asked
May 22
by
priyanka.c
1
answer
Due to the application of a force body of mass 1.5 kg is moving up vertically with an acceleration of $1.2 m/s^2$ for $10 \;s$, starting from rest, What is power of the agent doing work?
jeemain
physics
class11
unit4
work-power-energy
q42
medium
asked
Jul 22, 2013
by
meena.p
1
answer
A particle moves with velocity $v= (5 \hat i -3 \hat j+6 \hat k) m/s$ under the influence of a constant force $\hat F=(10 \hat i+10 \hat j+20 \hat k)N$. The instantaneous power applied to the particle is
jeemain
physics
class11
unit4
work-power-energy
q68
medium
asked
Aug 6, 2013
by
meena.p
1
answer
Power supplied to a particle of mass 2 kg varies with time is $P=\large\frac{3t^2}{2}$ watt, velocity of particle at $t=0$ is $v=0.$ The velocity of particle at $t=2s$ will be
jeemain
physics
class11
unit4
work-power-energy
q37
medium
asked
Jul 19, 2013
by
meena.p
1
answer
Velocity - time graph of a particle moving in a straight line is shown. Mass of particle is 2 kg work done by all the forces on the particle in time interval between $t=0$ to $t=10s$
jeemain
physics
class11
unit4
work-power-energy
q57
medium
asked
Aug 6, 2013
by
meena.p
1
answer
A particle of mass m moves in a straight line with its velocity varying with distance travelled according to the equation $v=a\sqrt {x}$ , where a is a constant. What is the total work done by all the forces during a displacement from x = 0 to x = d?
jeemain
physics
class11
work-power-energy
ch6
work
work-done-by-a-constant-force
easy
asked
Aug 25, 2014
by
balaji.thirumalai
1
answer
Ask Question
Tag:
Math
Phy
Chem
Bio
Other
SUBMIT QUESTION
►
Please Wait
Take Test
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
15 Test Series
JEEMAIN
350+ TESTS
NEET
320+ TESTS
CBSE XI MATH
50+ TESTS
CBSE XII MATH
80+ TESTS
...
X