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The smallest positive natural number $n$ such that $n!$ is divisible by $990$ is ?

$\begin{array}{1 1} 9 \\ 11 \\ 33 \\ 99 \end{array}$

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$990=9\times 10\times 11$
$\therefore $ the least natural number so that $n!$ is divisible by $990$ is 11
answered Aug 8, 2013 by rvidyagovindarajan_1
 

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