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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Work, Power and Energy

If momentum of boby increases by $0.01 %$ its kinetic energy will increase by

\[(a)\;0.01\;\% \quad (b)\;0.02\;\% \quad (c)\; 0.04 \;\%\quad (d)\;0.08\;\%\]

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$E\; \alpha\; P^2$
% increase in E= 2 $\times$ % increase in P
$\qquad=2 \times 0.01$
$\qquad=0.02 \%$
answered Aug 8, 2013 by meena.p

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