Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
0 votes

A spring 40 mm long is streched by application of a force. If 10 N force is required to stretch the spring through 1 mm, then work done in stretching the spring through 40 mm is

\[(a)\;84\;J \quad (b)\;68 \;J\quad (c)\; 23\;J \quad (d)\;8\;J\]
Can you answer this question?

1 Answer

0 votes
Since 10 N force is required to stretch through 1 mm
$\quad=\large\frac{1}{2} $$\times 10^4 \times (40 \times 10^{-3})^2$
$\quad = 8\;J$
Hence d is the correct answer. 


answered Aug 8, 2013 by meena.p
edited Feb 17, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App