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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Work, Power and Energy

A tennis ball dropped from height of $2m$ rebounds only $1.5 m, $ after hitting the ground , What fraction of energy is lost in the impact

\[(a)\;\frac{1}{2} \quad (b)\;\frac{1}{4}\quad (c)\; \frac{1}{8} \quad (d)\;\frac{1}{16}\]

1 Answer

Fraction of energy lost $=\large\frac{\Delta E}{E}$
$\large\frac{mg(h-h')}{mgh}=\frac{h-h'}{h}$
$=\large\frac{2-1.5}{2}=\frac{1}{4}$
Hence b is the correct answer.

 

answered Aug 8, 2013 by meena.p
edited Feb 17, 2014 by meena.p
 

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