Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Gravitation
0 votes

The value of eacape velocity on a certain planet is $ 2 km/s$ then the value of arbital speed for a satellite arbiting close to its surface is

$ a)\; 12 km/s \\b)\; 1 km/s \\c)\; 2\sqrt 2 km/s \\ d)\;\sqrt 2 km/s $
Can you answer this question?

1 Answer

0 votes
initial velocity $=\large\frac{escape\; velocity}{\sqrt 2}$
$v_0=\large\frac{2}{\sqrt 2}$$=\sqrt 2 \;km/s$
Hence d is the correct answer. 


answered Aug 9, 2013 by meena.p
edited Feb 17, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App