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A satellite moves in a circle around earth The radius of this circle is equal to one half of the radius of the moon's orbet. The satellite completes one revolution in

$ a)\;\frac{1}{2}\; lunar month \\ b)\; \frac{2}{3} \;lunar\; month \\ c) 2^{\frac{3}{2}} lunar\; month\; \\ d)\; 2^{\large\frac{-3}{2}} \;lunar\; month $

1 Answer

Time period of revolution of moon around earth=1 lunar month
Time period $ \alpha \; r^{\large\frac{3}{2}}$
$T_s=2^{-\large\frac{3}{2}}$ lunar month
Hence d is the correct answer.


answered Aug 9, 2013 by meena.p
edited Feb 17, 2014 by meena.p

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