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If the system of linear equations x+ky+3z=0 3x+ky−2z=0 2x+4y−3z=0 has

If the system of linear equations x+ky+3z=0 3x+ky−2z=0 2x+4y−3z=0 has a non-zero solution (x, y, z), then 2 xz y is equal to :

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