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Gravitation
Two satellites have their masses in the ratio $3:1$ The ratio of the orbit (circular ) are $1:4$ then the ratio of total mechanical energy of A and B
\[(a)\;\frac{12}{1} \quad (b)\;\frac{10}{1} \quad (c)\; \frac{8}{1} \quad (d)\;\frac{5}{1}\]
jeemain
physics
class11
unit6
gravitation
q12
easy
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asked
Aug 10, 2013
by
meena.p
retagged
Jul 10, 2014
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1 Answer
Energy $E=\large\frac{-GMm}{2r}$
$\large\frac{E_1}{E_2}=\frac{m_1}{r_1} \times \frac{r_2}{m_2}$
$\qquad=\bigg[\large\frac{m_1}{m_2}\bigg]\bigg[\large\frac{r_2}{r_1}\bigg]$
$\qquad=\large\frac{3}{1} \times \frac{4}{1}=\frac{12}{1}$
Hence a is the correct answer.
answered
Aug 10, 2013
by
meena.p
edited
Feb 17, 2014
by
meena.p
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