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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Gravitation

A particle of mass 10 g is kept on surface of a uniform sphere of mass 100 kg and radius 10 cm. Find the work done against gravitational force between them, to take the particle for away from sphere $(G=6.67 \times 10^{-11} Nm^2/kg)$

\[(a)\;3.33 \times 10^{-10} \;J \quad (b)\;13.34 \times 10^{-10}\;J \quad (c)\; 6.67 \times 10^{-9}\;J \quad (d)\;6.67 \times 10^{-10}\;J\]
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1 Answer

$\Delta W= Work done=v_f-u_i$
$\qquad= 0 -\bigg[\large\frac{-GMm}{R}\bigg]$
$\Delta W=\large\frac{6.67 \times 10^{-11} \times 100}{0.1} \times \frac{10}{1000}$
$\qquad= 6.67 \times 10^{-10}J$
hence d is the correct  answer.

 

answered Aug 11, 2013 by meena.p
edited Feb 17, 2014 by meena.p
 

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