$\begin{array}{1 1} 66 \\ 65 \\ 57 \\ 56 \end{array}$

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No. of points $=12$

To draw a line two points are required.

If no three points are collinear then the no. of lines = $^{12}C_2$

Since 5 points are collinear, using these 5 points we can draw only one line.

$\therefore$ The no. of different lines $=^{12}C_2-^5C_2+1$ (single line using collinear points)

$=66-10+1=57$

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