The reaction between aluminium carbide and water takes place according to the following equation:$Al_4C_3+12H_2O \longrightarrow 3CH_4+4Al(OH)_3$ calculate the volume of $C H_4$ released from $14.4\;g$ of $Al_4 C_3$ by excess water at S.T.P. $(C = 12, Al = 27)$

Question

$\begin{array}{1 1} (a)\; 7.2\; litres \\ (b)\;8.4\; litres \\ (c)\;6.23\; litres \\ (d)\;6.72 \;litres \end{array} $