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If one person shakes hand with another only once,the no. of hand shakes is 66. How many persons are there?

$\begin{array}{1 1} 10 \\ 12 \\ 24 \\ 33 \end{array}$

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Let there be $ n$ persons.
Each hand shakes with other only once.
$\therefore$ No. of hand shakes = $^nC_2=66\:(given)$
$\Rightarrow\:n=12\:or\:-11\:(not \:possible)$
The no. of persons =$12$
answered Aug 13, 2013 by rvidyagovindarajan_1

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