$\begin{array}{1 1} 6210 \\ 5040 \\ 1110 \\ 385 \end{array}$

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No. of candidates = 10

A voter can vote at the most 4 candidates and alteast one candidate.

No. of ways in which he can vote for 1 candidate = $^{10}C_1=10$

No. of ways in which he can vote for 2 candidate = $^{10}C_2=45$

No. of ways in which he can vote for 3 candidate = $^{10}C_3=120$

No. of ways in which he can vote for 4 candidate = $^{10}C_4=210$

$\therefore$ The required no. of ways = $10+45+120+210=385$

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