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Permutations and Combinations
In an examination a candidate has to pass in each of the four subjects. In how many ways he can fail?
$\begin{array}{1 1} 16 \\ 14 \\ 24 \\ 15 \end{array}$
jeemain
math
class11
ch7
permutations-and-combinations
fundamental-principle-of-counting
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asked
Aug 13, 2013
by
rvidyagovindarajan_1
edited
Apr 6, 2016
by
meena.p
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1 Answer
No. of ways in which one can pass or fail in the examination = $2^4=16$
To pass one has to pass in all the subjects.= 1 way
$\therefore$ The no. of ways in which one can fail = 16-1=15 ways.
answered
Aug 13, 2013
by
rvidyagovindarajan_1
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