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Q)

The number of ways in which $4n$ students can be distributed equally among $4$ sections = ?

$\begin{array}{1 1} \large\frac{(4n)!}{n!} \\ \large\frac{(4n)!}{4!n!} \\ \large\frac{(4n)!}{n!^{4}} \\ \large\frac{(4n)!}{4!n!^{4}} \end{array}$

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