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Four dice are rolled. The no. of possible outcomes in which at least one dice shows 2 is ?

$\begin{array}{1 1} 1296 \\ 671 \\ 625 \\ 585 \end{array}$

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No. of ways in which any number appearing in one dice = 6
No. of ways in which 2 appear in one dice = 1
No. of ways in which 2 does not appear in one dice = 5
There are 4 dice.
Getting 2 in atleast one dice =
Getting any number in all the 4 dice - Getting not 2 in any of the 4 dice.
$=(6\times 6\times 6\times 6)-(5\times 5\times \times 5\times 5)$
$1296-625=671$
answered Aug 14, 2013 by rvidyagovindarajan_1
 

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