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# The dissociation constant of a substituted benzoic acid at $25C$ is $1.0 \times 10^{-4}$. The $p^{H}$ of $0.01\;M$ solution its sodium salt is

$\begin{array}{1 1} (a)\;0 \\(b)\;1 \\ (c)\;7 \\ (d)\;8 \end{array}$

$P^{H} =+\large\frac{1}{2}$$(P^kW+P^{k}a+\log C) \qquad= \large\frac{1}{2}$$\times 14 +\large\frac{1}{2} $$\times 4 +\large\frac{1}{2}$$\log 10^{-1}$
$\qquad= 7+2-1=8$