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Permutations and Combinations
How many 10 digit numbers are there using the digits 1 and 2 ?
$\begin{array}{1 1} (A)\;^{10}C_1+^9C_1 \\ (B) \;2^{10} \\ (C) ^{10}C_2 \\ (D) 10! \end{array}$
jeemain
math
class11
ch7
permutations-and-combinations
fundamental-principle-of-counting
easy
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asked
Aug 15, 2013
by
rvidyagovindarajan_1
edited
Apr 5, 2016
by
meena.p
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1 Answer
Each place can be fixed by any of the two digits.
$\therefore$The required 10 digit numbers = $2^{10}$
answered
Aug 15, 2013
by
rvidyagovindarajan_1
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