$\begin{array}{1 1} 18 \\ 36 \\ 108 \\ 432 \end{array}$

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Fixing 3 in unit place there are $3!=6$ numbers.

Fixing 4 in unit place there are $3!=6$ numbers

Similarly by fixing 4 and 5 in unit place we get 6 numbers in each

$\therefore$ Each of the digits 3,4,5,6 come in unit place in 6 numbers

$\therefore$ The sum of the digits in unit place of the the numbers=

$6\times (3+4+5+6)=108$

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