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Total no. of words with or without meaning formed by 3 vowels and 3 consonants taken from 5 vowels and 6 consonants is?

$\begin{array}{1 1} 200 \\ 720 \\ 1400 \\ 14000 \end{array}$

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First of all selection of alphabets are to be done.
3 vowels and 3 consonants can be selected in $^5C_3.^6C_3$ ways
Then they are to be arranged
This can be done in $6!$ ways.
$\therefore$ The required no. of words = $^5C_3.^6C_3.6!$
$=10\times 20\times 720=144000$
answered Aug 15, 2013 by rvidyagovindarajan_1

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