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# Equal volumes of three basic solutions of 11,12 and 13 are mixed in a vesel. What will be the concentration in the mixture ?

$\begin{array}{1 1} (a)\;1.11 \times 10^{-11}\;M \\(b)\;3.7 \times 10^{-12} \\ (c)\;3.7 \times 10^{-11}\;M\\ (d)\;1.11 \times 10^{-22}\;M \end{array}$

$[H^{+}]$ ions concentrations are $10^{-11},10^{-12}$ and $10^{-13}$ on mixing equal volumes $[H^{+}]$ in final solution .
$\qquad= \large\frac{10 \times 10^{-12} + 1 \times 10^{-42}}{3}$
$\qquad= \large\frac{11.1 \times 10^{-42}}{3}$$= 3.7 \times 10^{-12}\;M$