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Questions  >>  SAT  >>  Chemistry  >>  chemical equilibrium

The equilibrium constant for the reaction $2SO_2(g)+O_2(g) \to 2SO_3(g)$ would be :

$\begin{array}{1 1} (a)\; K= 2[SO_3]/2[SO_2][O_2] \\ (b)\; K= 2[SO_2]/[O_2][SO_3] \\ (c) \;[SO_3]^2[SO_2]^2[O_2] \\ (d)\; [SO_2]^2[O_2]/[SO_3]^2 \end{array} $

1 Answer

Solution :
Using the chemical reaction given above, we can rewrite the Equilibrium constant expression to reflect concentration. The concentration is molarity, written as moles per liter (M=mol/L).
The products are in the numerator and those of the reactants are in the denominator. The equation is a function of the concentrations, the upper case letters are the molar concentrations of the reactants and products (A, B etc.).
The lowercase letters are the stoichiometric coefficients that balance the equation.
Hence Answer is $K = [SO_3]^2/[SO_2]^2[O_2]$
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