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# The equilibrium constant for the reaction $2SO_2(g)+O_2(g) \to 2SO_3(g)$ would be :

$\begin{array}{1 1} (a)\; K= 2[SO_3]/2[SO_2][O_2] \\ (b)\; K= 2[SO_2]/[O_2][SO_3] \\ (c) \;[SO_3]^2[SO_2]^2[O_2] \\ (d)\; [SO_2]^2[O_2]/[SO_3]^2 \end{array}$

$K_c=[C]^c[D]^d/[A]^a[B]^b$
Hence Answer is $K = [SO_3]^2/[SO_2]^2[O_2]$