The molar solubility products is $K_{sp}$. 's' is given in terms of $K_{sp}$ by the relation

Question

( A ) $s = (\frac{K_{sp}}{128})^{^{1/4}}$
( B ) $s = (\frac{K_{sp}}{256})^{^{1/5}}$
( C ) $s = (128 K_{sp})^{^{1/4}}$
( D ) $s = (256 K_{sp})^{^{1/5}}$