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Q)

A satellite revolving roung the earth with orbital speed $v_0$, If it stops suddenly, the speed with which it will strike the surface of the earth would be (-ve escape velocity of the particle on earth's surface)

$(a)\;\frac{v_e^2}{v_0} \quad (b)\; v_0 \quad (c)\;\sqrt {v_e^2-v_0^2} \quad (d)\;\sqrt {v_e^2-2 v_0^2}$

$v_0^2 =\large\frac{GM}{r}$
$KE$=change in potential energy
$\large\frac{1}{2}$$mv^2 =\large\frac{-GMm}{r}-\bigg(\large\frac{-GMm}{R}\bigg)$
$v^2=\large\frac{2GM}{R}-\frac{2GM}{r}$
$\qquad= v_e^2 -2 v_0^2$
$v=\sqrt {v_e^2-2v_0^2}$